Count to 100! - Printable Version +- howtothings.co.uk (https://www.howtothings.co.uk) +-- Forum: Open Discussion (https://www.howtothings.co.uk/forumdisplay.php?fid=5) +--- Forum: The Lounge (https://www.howtothings.co.uk/forumdisplay.php?fid=18) +--- Thread: Count to 100! (/showthread.php?tid=746) |
RE: Count to 100! - T3hRogue - 13-02-2011 Fuck it, 18 RE: Count to 100! - bigsharn - 13-02-2011 RE: Count to 100! - WARLORDTF - 14-02-2011 vo=14m/s θ°=45 degrees yo=0 find R The motion of an object moving near the surface of the earth can be described using the equations: (1): x = xo + vxo·t (2): y = yo + vyo·t - 0.5·g·t2 The calculator solves these two simultaneous equations to obtain a description of the ballistic trajectory. The horizontal and vertical components of initial velocity are determined from: vxo = vo·cos θ vyo = vo·sin θ Then the calculator computes the time to reach the maximum height by finding the time at which vertical velocity becomes zero: vy = vyo - g·t trise = vyo/g Maximum height is obtained by substitution of this time into equation (2). h = yo + vyo·t - 0.5·g·t2 Next, the time to fall from the maximum height is computed by solving equation (2) for an object dropped from the maximum height with zero initial velocity. 0 = h - 0.5·g·t2 tfall = √(2·h/g) The total flight time of the projectile is then: tflight = trise + tfall From this, equation (1) gives the maximum range: range = vxo·tflight |